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Geetanjali Mahobiya
2 months ago | [YT] | 0
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Geetanjali Mahobiya
3 months ago | [YT] | 0
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Geetanjali Mahobiya
Remove duplicate from sorted array ...
Approach
Optimized Approach (Two Pointers)
💡 Idea
Because the array is sorted, duplicates are always next to each other.
We maintain:
i → slow pointer (position of last unique element)
j → fast pointer (to scan array)
Whenever we find a new unique element, we move i forward and copy that element.
🧠Algorithm Steps
If array length is 0 → return 0
Initialize i = 0
Loop j from 1 to n-1:
If nums[j] != nums[i]
Increment i
nums[i] = nums[j]
Return i + 1 (count of unique elements)
4 months ago | [YT] | 2
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Geetanjali Mahobiya
Happy achievement 🎊
9 months ago | [YT] | 2
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Geetanjali Mahobiya
1 year ago | [YT] | 0
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Geetanjali Mahobiya
Which of the following statement is correct about array?
1 year ago | [YT] | 0
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