Gina Womack

On Prayer; For believers and Not.
I see many persons, religious and non, confused about the method, practicality and expectations of the practice of prayer.


I know that I have seen many speak about praying to a God Above as a Christian but when Jesus was asked where the Kingdom of God was He spoke this; "For it is not a place that you will see and say, "Oh there it is" or "Oh Here it is" for the Kingdom of God is within us. Jesus also told us that God is Spirit, inside all of us.


The Book of Job: 10: 7-12 tells us also that God is within all the creatures and the things that make up our world, even the Earth itself.


Jesus also taught that when we pray, we are not to ask for things because the God within us knows our needs. Jesus spoke on how to pray, and he taught; ask for the daily bread, ask for forgiveness and how to forgive others, and keeping the mindset to avoid the temptations we are weak to. He specifically stated there should be no other empty phrases, no public displays.


When many sit to eat they say Grace, some call it prayer, but it is also known as a meditation, a moment to envision the things you are grateful for, a moment to remember the things that give you a smile or give way to a released breath of tension.


The world is hard, it's important for us to retain balance as a practice so that we do not give way to the sensationalized and overtly negative framing of social media and the news.


Some may say that prayer is not the same as meditation, but I will tell you that Jesus was known to go into solitude to meditate. As Jesus taught that God was within us, a meditation with yourself is a meditation with the Spirit of God within us all.

And you may say, there is no God within me, there is no Heaven or Hell within me. To this I would say "A rose by any other name smells as sweet".


Most of us have inner dialog, most of have feelings of remorse, sadness, and joy. These are the results of the judgements of our actions by that God that resides in us all.


All of us mourn our lost family and friends, this is not a taught response but a part of that Holy Connection between all of creation. This is true amongst the Great Apes like Humans all the way down to our friendly pets.


When we break out and song, dance or start humming and bee bopping, this is an expression of that Spirit of the God within us all. These are some of the good things we do that add to our own lives and those around us.


However, we also have a bad God within us. Some of us have found a path or have been borne with the innate desire and joy to hurt others, to deceive them and to even steal from them the greatest of gifts, Joy, Happiness and Serenity.


When we sit around and complain and moan, we are building neural pathways in our brains that make it easier to identify those things you focus on. The more you look for evil, the more you will find it.


However, when we sit around and think of things that bring us inner peace and contentment, we are speaking and feeding that good God within us all. We are making our minds acutely aware of what sustains and edifies us. The more we can recognize goodness, the more goodness we will encounter.


For if ye seek, so shall ye find it.


What are you looking for?

3 weeks ago (edited) | [YT] | 0

Gina Womack

Who is the Liar?

6 months ago | [YT] | 0

Gina Womack

I spent a week debating the origins of Science and Math being rooted in Religion in a Science forum hehe. 750+/- Comments between 105 commenters. Fun to discuss Ramanjuan and his Goddess, the Origin of Thought and the limits of Science

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2 years ago | [YT] | 0

Gina Womack

This segment of calculating distances by hand will work with perspective and projected geometry. In particular this segment will discuss obtaining accurate distance calculations from the use of photographs. For these calculations to work, a few control points are needed. These control points will be a known distance apart from each other. As a working example, let’s say we want to know how high off the ground a point is off the ground. For this example, we will use a flag pole with our inquiry being how high off the ground is the bottom of the flag.
For this example, our control points will be the pole’s access port. We will assume this has been field measured (RED) and that this port is 36” above ground level and 9” in height. We will need to calculate the remaining distance between the top of the access port and the bottom of the flag. A yard stick with known points would make a perfect tool for these calculations and as simple as standing the stick vertically along the pole so that the markings are visible in the photo.

In order to achieve the calculation needed to provide us with the missing dimension, we will gather some data from the picture, specifically the same distances measured in pixels (BLUE) where 36″ = 55px, 9″ =15px and X = 240px.
The Cross Ratio Formula
AC · BD = A’C’ · B’D’
BC · AD B’C’ · A’D’
We will utilize a practical concept in projective geometry known as cross-ratios to accurately provide the unknown distance in inches (X) utilizing the below equation.
The terms (AC, BD, etc) refer to the photo distances
between points in question (pA, pB, etc) [Blue]
The terms (A’C’, B’D’, etc) refer to the real distances
between points in question (pA, pB, etc) [Red]
Photo (pixels) Real (inches)
70 · 255 = 45 · ( 9 + X)
15 · 310 9 · (45 + X)

17,850 = 45 · ( 9 + X)
4,650 9 · (45 + X)

3.8387 = 45 · ( 9 + X)
9 · (45 + X)

This simplifies to;
X = 1149.677145
10.451619
Or X = 109.999991” (X = 9’-2”)
For this example, the bottom of the flag would be 12’-11” above ground level.
Below is the expanded mathematics.
55px 15px 240px Referencing the photo above;
dA dB dC pA = ground level
|--------+----+-----------------------| pB = bottom of port
pA pB pC pD pC = top of port
dA’ dB’ dC’ pD = bottom of flag
36in 9in X in

AC · BD = A'C' · B'D'
BC · AD B’C’ · A’D’

AC = 70px [ dA+dB ] A’C’ = 45in
BD = 255px [ dB+dC ] B’D’ = X + 9in
BC = 15px [ dB ] B’C’ = 9in
AD = 310px [dA+dB+dC] A’D’ = X + 45in
Using the information diagram above; the long hand math follows below.
First, we will calculate the cross ratio for the photo or known quantities. We only need a ratio so we do not need to worry over the unit of measure (pixels, inches, etc.)
(55 + 15)· (15 + 240) => 70 · 255 => 17,850 => 3.83870967741
15 · (55 +15 + 240) 15 · 310 4,650
Next, we will analyze the real-world quantities.
(36 + 9) · (9 + X) => 45 · (9 + X)
9 · (36 + 9 + X) 9 · (45 + X)
Since the cross ratios of both units of measure remain the same, we can now say;
45 · (9 + X) = 3.83870967741
9 · (45 + X)
A) Firstly, we will simplify the problem by removing the fraction.
We will multiply both sides by the denominator. [ 9 * (45 + X) ]
Side A:
45 · (9 + X) · (9 · (45 + X))
9 · (45 + X)

= 45 · (9 + X)
Side B:
3.838709 · (9 · (45 + X))

= 34.548381 · (45 + X)
We now have the equation; 45 · (9 + X) = 34.548381 · (45 + X)
B) Now we can expand both sides of the equation.
Side A:
45 · (9 + X)
= ((45 · 9) + (45 · X))
= 405 + 45X
Side B:
34.548381 · (45 + X)
= 34.548381 · ((34.548381 · 45) + (34.548381 · X))
= 1554.677145 + 34.548381X
We now have the equation; 405 + 45X = 1554.677145 + 34.548381X
C) We will now remove the known term from the left side of the equation.
Subtracting this quantity from both sides of the equation. [ 405 ]
Side A:
405 + 45X – 405
= 45X
Side B:
1554.677145 + 34.548381X – 405
= 1149.677145 + 34.548381X
We now have the equation; 45X = 1149.677145 + 34.548381X
D) We will now remove the multiplier to X from the right side of the equation.
Subtract the X quantity from both sides of the equation. [ 34.548381X ]
Side A:
45X - 34.548381X
= 10.451619X
Side B:
1149.677145 + 34.548381X - 34.548381X
= 1149.677145
We now have the equation; 10.451619X = 1149.677145
E) We can now simplify the equation by dividing each quantity by the multiplier of X.
We are left with our solution in the form of; X = Missing Quantity.
Divide each side by the X multiplier. [ 10.451619 ]
Side A:
10.451619X = X
10.451619
Side B:
1149.677145 = 109.999910
10.451619
We now have the equation; X = 109.999910”
F) We now have the solution for dC’ ( X ) for real-world distances.
This amount is in the original unit of measure for the real world distances.
Round this number to the nearest whole number for ease. [ 110″]
110in/12in = 9.166659ft => 9ft + 0.166659ft


12in · 0.166659 = 1.999in
We now have the simplified answer; dC’ & X = 9ft 2in
G) We can now say that the total real-world distance;
dA’ + dB’ + dC’ => 36in + 9in + 110in = 155in
155in / 12in
= 12.916666ft
= 12ft + 0.916666ft

=> 12in · 0.916666 = 11in
H) The full answer to our inquiry regarding the height of point D (pD).
12ft 11in above ground

2 years ago | [YT] | 1

Gina Womack

Coming Soon, Coding Practice in VB for Perspective Geometry Calculator.

2 years ago | [YT] | 1

Gina Womack

2 years ago | [YT] | 1